< Ideal gas lawRevision as of 07:00, 7 January 2009 by imported>Paul Wormer
- All gases mentioned below are assumed to be ideal, i.e. their p, V, T dependence is given by the ideal gas law.
- The molar gas constant R = 0.082057 atm⋅L/(K⋅mol)
Example problems
Problem 1
Determine the volume of 1 mol of ideal gas at pressure 1 atm and temperature 20 °C.

Problem 2
Compute from Charles' and Gay-Lussac's law (V/T is constant) the volume of an ideal gas at 1 atm and 0 °C (Use the final result of the previous problem). Write VT for the volume at T °C, then

Problem 3
A certain amount of gas that has an initial pressure of 1 atm and an initial volume of 2 L, is compressed to a final pressure of 5 atm at constant temperature. What is the final volume of the gas?
Boyle's law (pV is constant)

or

Inserting the given numbers

Ideal gas law
The number n of moles is constant

It is given that the initial and final temperature are equal,
, therefore the products RT on both sides of the equation cancel, and Eq. (1.4) reduces to Eq. (1.1).
Problem 4
How many moles of nitrogen are present in a 50 L tank at 25 °C when the pressure is 10 atm? Numbers include only 3 significant figures.
